(3p^2-3p+3)-(p^2-3p+6)=

Solution for (3p^2-3p+3)-(p^2-3p+6)= equation:

Simplifying
(3p2 + -3p + 3) + -1(p2 + -3p + 6) = 0

Reorder the terms:
(3 + -3p + 3p2) + -1(p2 + -3p + 6) = 0

Remove parenthesis around (3 + -3p + 3p2)
3 + -3p + 3p2 + -1(p2 + -3p + 6) = 0

Reorder the terms:
3 + -3p + 3p2 + -1(6 + -3p + p2) = 0
3 + -3p + 3p2 + (6 * -1 + -3p * -1 + p2 * -1) = 0
3 + -3p + 3p2 + (-6 + 3p + -1p2) = 0

Reorder the terms:
3 + -6 + -3p + 3p + 3p2 + -1p2 = 0

Combine like terms: 3 + -6 = -3
-3 + -3p + 3p + 3p2 + -1p2 = 0

Combine like terms: -3p + 3p = 0
-3 + 0 + 3p2 + -1p2 = 0
-3 + 3p2 + -1p2 = 0

Combine like terms: 3p2 + -1p2 = 2p2
-3 + 2p2 = 0

Solving
-3 + 2p2 = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 2p2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 2p2 = 0 + 3
2p2 = 0 + 3

Combine like terms: 0 + 3 = 3
2p2 = 3

Divide each side by '2'.
p2 = 1.5

Simplifying
p2 = 1.5

Take the square root of each side:
p = {-1.224744871, 1.224744871}